40=(2)^x

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Solution for 40=(2)^x equation: 



40=(2)^x

We move all terms to the left:

40-((2)^x)=0

determiningTheFunctionDomain
-2^x+40=0

We move all terms containing x to the left, all other terms to the right

-2^x=-40

x=-40/1

x=-40

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